Darcy friction factor calculator
Result
- Darcy friction factor
- 0.0223
- Fanning friction factor
- 0.0056
- Flow regime
- Turbulent
Apply this friction factor across a branched or looped network in the Studio.
Open the Studio →The Darcy friction factor sets how much head a pipe loses to wall friction. This calculator returns it from the Reynolds number and the relative roughness, using the Colebrook-White equation in the turbulent range: the same relationship the Moody chart plots and that Fluid Network Studio solves internally.
Method
- Laminar (
Re < 2300):f = 64 / Re, independent of roughness. - Turbulent: the Colebrook-White equation,
1 / sqrt(f) = -2 log10( (epsilon/D) / 3.7 + 2.51 / (Re sqrt(f)) )
where epsilon/D is the relative roughness. It is implicit in f, so it is solved iteratively; the explicit Swamee-Jain equation is a good approximation and starting guess. The Moody chart is the graphical form of these relationships. Fluid Network Studio evaluates it with the Churchill (1977) correlation, an explicit form that reproduces Colebrook-White across all regimes.
This is the Darcy friction factor. The Fanning friction factor used in some chemical-engineering texts is one quarter of it (f_Darcy = 4 f_Fanning). Citation: Colebrook, C. F. (1939); Moody, L. F. (1944).
Limits. Fully developed, single-phase flow in a circular pipe. In the transitional band (roughly Re 2300 to 4000) the factor is uncertain and both correlations should be treated with caution.
Inputs
- Reynolds number (or fluid, velocity and diameter to compute it).
- Relative roughness
epsilon/D, or absolute roughness epsilon (mm) with diameter D (mm).
Outputs
- Darcy friction factor f.
- Flow regime, and the equivalent Fanning factor.
Worked example
Turbulent: Re = 100,000 and relative roughness epsilon/D = 0.001 give, from Colebrook-White, f = 0.0222.
Laminar: Re = 1500 gives f = 64 / 1500 = 0.0427, regardless of roughness.
Frequently asked questions
Darcy or Fanning?
This is the Darcy factor. Multiply the Fanning factor by four to get it, or divide Darcy by four to get Fanning.
Why is it iterative?
The Colebrook-White equation has f on both sides, so it cannot be rearranged for f in closed form. The solver iterates to convergence; the Swamee-Jain equation gives an explicit value within about 1 per cent.
Related
- Reynolds number calculator
- Pipe flow and pressure drop calculator
- Open the Studio for full networks.
New to the terms? See the glossary and how it works, or browse all calculators.